What value of $t > 1$ satisfies the equation ∫1t1xdx=3−1t\int_{1}^{t}\frac{1}{\sqrt{x}}dx = 3 - \frac{1}{t}∫1tx1dx=3−t1?
(1+2)2+12\frac{\left(1+\sqrt{2}\right)^2+1}{2}2(1+2)2+1
(1−2)2\left(1-\sqrt{2}\right)^2(1−2)2
14\frac{1}{4}41
(1+2)2\left(1+\sqrt{2}\right)^2(1+2)2
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AI Tutor 3:49 AM
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