Particle Position From Velocity Vector

A particle moving in the $xy$-plane has a velocity vector given by $\displaystyle \mathbf{v}(t) = \left\langle \frac{1}{t+1}, t e^{-t} \right\rangle$ for time $\displaystyle t \ge 0$. If the particle’s position is $\displaystyle (-1, 2)$ at time $\displaystyle t=0$, what is its distance from the origin at time $\displaystyle t=2$?