For each of the vector–valued functions above (with time $$t$$ in an appropriate interval), the acceleration vector is found by differentiating each component twice. Rank the functions in order of increasing magnitude of the acceleration vector at the specified evaluation point: use $$t = 1$$ for Functions 1, 3, and 4; and $$t = \frac{\pi}{6}$$ for Function 2. (Recall that for a vector function $$\vec{r}(t) = \langle x(t), y(t) \rangle$$, the acceleration magnitude is given by $$|\vec{a}(t)| = \sqrt{(x''(t))^2+(y''(t))^2}.$$)
| Function | $$\vec{r}(t)$$ |
|---|---|
| Function 1 | $$\langle t, t^2 \rangle$$ |
| Function 2 | $$\langle \cos(t), \sin(t) \rangle$$ |
| Function 3 | $$\langle e^t, e^t \rangle$$ |
| Function 4 | $$\langle t^2, \ln(t+1) \rangle$$ |
Function 2, Function 1, Function 4, Function 3
Function 2, Function 4, Function 1, Function 3
Function 1, Function 2, Function 4, Function 3
Function 1, Function 4, Function 2, Function 3
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