Slope of a Parametric Curve
A particle moves in the $$xy$$-plane so that its position for $$t \geq 0$$ is given by the parametric equations $$x = \ln(t + 1)$$ and $$y = kt^2$$, where $$k$$ is a positive constant. The line tangent to the particle’s path at the point where $$t = 3$$ has slope $$8$$. What is the value of $$k$$?
A
$$\displaystyle \frac{16}{3}$$
B
$$\displaystyle \frac{4}{3}$$
C
$$\displaystyle \frac{1}{3}$$
D
$$\displaystyle \frac{1}{192}$$
Question Leaderboard
Not enough data yet to show leaderboard.
APFIVE