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Solving a Parametric Position Equation

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A particle moves along a path with positions given by
x(t)=t2+4∗t+4t+2x(t)=\frac{t^2+4*t+4}{t+2} and
y(t)=9∗t2+12∗t+4t2+4∗t+4.y(t)=\sqrt{\frac{9*t^2+12*t+4}{t^2+4*t+4}}.
Find the value of tt for which x(t)+y(t)=8.x(t)+y(t)=8.

A

t=1−412t=\frac{1-\sqrt{41}}{2}

B

t=2t=2

C

t=1+412t=\frac{1+\sqrt{41}}{2}

D

t=3t=3

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