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Solving a Radical Equation with Absolute Values

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What is the solution to the equation 16t2+48t+36−4t+6t2+3t+2.25=t2 \sqrt{16t^2+48t+36}-\frac{4t+6}{\sqrt{t^2+3t+2.25}}=\frac{t}{2} ?

A

t=47t=\frac{4}{7}

B

t=23t=\frac{2}{3}

C

t=−23t=-\frac{2}{3}

D

t=−47t=-\frac{4}{7}

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