Solving an Absolute Value Radical Equation
Solve the equation
$$\sqrt{25*t^2+10*t+1}-\frac{5*t+2}{\sqrt{t^2+0.4*t+0.04}}=\sum_{n=1}^{1} n$$
for $$t$$.
| Step | Expression |
|---|
- Recognize: $$\sqrt{25*t^2+10*t+1}=|5*t+1|$$ and $$\sqrt{t^2+0.4*t+0.04}=|t+0.2|$$
- Equation becomes: $$|5*t+1|-\frac{5*t+2}{|t+0.2|}=1$$
- Assuming positive expressions leads to: \((5*t+1)-\frac{5*t+2}{t+0.2}=1\) and simplifies to a quadratic: $$5*t^2-4*t-2=0.$$
A
$$t=\frac{-2+\sqrt{14}}{5}$$
B
$$t=\frac{2-\sqrt{14}}{5}$$
C
$$t=\frac{-2-\sqrt{14}}{5}$$
D
$$t=\frac{2+\sqrt{14}}{5}$$
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