Velocity Vector for Parametric Equations

Question

The position of a particle is given by the parametric equations $$x(t) = \sin(2t)$$, $$y(t) = t^2 + 1$$. What is the velocity vector at time $$t = \displaystyle\frac{\pi}{4}$$?

Accepted Answer

$$\langle 0, \displaystyle\frac{\pi}{2} \rangle$$

Answer

$$\langle 0, \pi \rangle$$

Answer

$$\langle 1, \displaystyle\frac{\pi}{2} \rangle$$

Answer

$$\langle 2, \displaystyle\frac{\pi}{2} \rangle$$

Rank	User	Correct Count	Attempt Count	Total Time	Score
#1	yeee5864	1	1	0m 37s	63
#2	wangwanqioier	1	1	0m 55s	45
#3	lluatic	1	1	1m 01s	39
#4	y.seong2027	0	1	1m 28s	-98

Velocity Vector for Parametric Equations

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