Velocity Vector From Parametric Equations

Question

The position of a particle moving in the xy-plane is described by the parametric equations $$x(t) = t^2 \sin(t)$$ and $$y(t) = \displaystyle\frac{1}{t+1}$$. What is the velocity vector of the particle at time $$t = \pi$$?

Accepted Answer

$$\langle -\pi^2, -\displaystyle\frac{1}{(\pi+1)^2} \rangle$$

Answer

$$\langle -\pi^2, \displaystyle\frac{1}{(\pi+1)^2} \rangle$$

Answer

$$\langle 2\pi, -\displaystyle\frac{1}{(\pi+1)^2} \rangle$$

Answer

$$\langle \pi^2, -\displaystyle\frac{1}{(\pi+1)^2} \rangle$$

Velocity Vector From Parametric Equations

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