Periodic Trends and Halogen Reactivity
The observation that fluorine is more reactive than iodine, despite its smaller atomic radius, is best explained by which of the following?
A
F has lower ionization energy than iodine
B
F has higher electronegativity and stronger electron affinity
C
F has more protons, creating stronger nuclear attraction
D
F has fewer electron shells, reducing electron repulsion
Question Leaderboard
| Rank | |||||
|---|---|---|---|---|---|
| #1 | misop0709 | 2 | 2 | 0m 00s | 200 |
| #2 | itzzhanachan | 1 | 1 | 0m 00s | 100 |
| #3 | rowidaabdelhakeem | 1 | 1 | 0m 00s | 100 |
| #4 | sjhjohnston09 | 1 | 1 | 0m 09s | 91 |
| #5 | trnrity | 1 | 1 | 0m 13s | 87 |
| #6 | mahima6129 | 1 | 1 | 0m 14s | 86 |
| #7 | heodavidheo | 1 | 1 | 0m 16s | 84 |
| #8 | 10024453 | 1 | 1 | 0m 17s | 83 |
| #9 | selenavuong2009 | 1 | 1 | 0m 17s | 83 |
| #10 | ariannapanameno11 | 1 | 2 | 0m 40s | 50 |
Items per page:
10
1 – 10 of 18
