APFIVE Periodic Trends and Halogen Reactivity
The observation that fluorine is more reactive than iodine, despite its smaller atomic radius, is best explained by which of the following?
A
F has higher electronegativity and stronger electron affinity
B
F has more protons, creating stronger nuclear attraction
C
F has lower ionization energy than iodine
D
F has fewer electron shells, reducing electron repulsion
Question Leaderboard
| Rank | |||||
|---|---|---|---|---|---|
| #1 | misop0709 | 2 | 2 | 0m 00s | 200 |
| #2 | itzzhanachan | 1 | 1 | 0m 00s | 100 |
| #3 | rowidaabdelhakeem | 1 | 1 | 0m 00s | 100 |
| #4 | mahima6129 | 1 | 1 | 0m 14s | 86 |
| #5 | selenavuong2009 | 1 | 1 | 0m 17s | 83 |
| #6 | 10108343 | 1 | 1 | 1m 18s | 22 |
| #7 | eiaadev | 1 | 1 | 2m 39s | -59 |
| #8 | kat.poirier05 | 1 | 1 | 9m 35s | -475 |
| #9 | Derinchiay2013 | 2 | 2 | 12m 30s | -550 |
Items per page:
10
1 – 9 of 9