APFIVE Conductivity Ratio of Ionic Solutions
In aqueous solution, the conductivity is proportional to the product of the number of ions and their mobility. Given that NaCl dissociates into 2 ions with a mobility factor of 1.00 and CaCl2 into 3 ions with a mobility factor of 0.80, calculate the ratio of the conductivity of a CaCl2 solution to that of a NaCl solution at the same molarity.
| Compound | Number of Ions per Formula Unit | Relative Ion Mobility Factor |
|---|---|---|
| NaCl | 2 | 1.00 |
| CaCl2 | 3 | 0.80 |
A
Approximately 1.6 times greater
B
Approximately 1.2 times greater
C
Approximately equal
D
Approximately 0.8 times as high
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