Redox Reaction Stoichiometry
In acidic solution, the half-reaction for permanganate ion is given by $$MnO_4^- + 8*H^+ + 5e^- \rightarrow Mn^{2+} + 4*H_2O$$. If 0.1 moles of electrons are passed through the solution, how many moles of $$KMnO_4$$ (which supplies the $$MnO_4^-$$) are reduced?
A
0.02 moles
B
0.5 moles
C
0.05 moles
D
0.10 moles
Question Leaderboard
| Rank | |||||
|---|---|---|---|---|---|
| #1 | itzzhanachan | 1 | 1 | 0m 00s | 100 |
| #2 | heodavidheo | 1 | 3 | 0m 00s | 80 |
| #3 | Derinchiay2013 | 3 | 6 | 5m 32s | -62 |
Items per page:
10
1 – 3 of 3
APFIVE