Given the following reactions and their standard enthalpy changes:

N₂(g) + 3H₂(g) → 2NH₃(g) ΔH° = -92.2 kJ/mol
N₂(g) + O₂(g) → 2NO(g) ΔH° = +180.6 kJ/mol
H₂(g) + ½O₂(g) → H₂O(g) ΔH° = -241.8 kJ/mol

What is the standard enthalpy change, ΔH°, for the reaction represented by the equation below?

4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(g)