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AP Chemistry/Unit 7: Equilibrium
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Calculating Molar Solubility from Ksp

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The solubility product constant, KspK_{sp}, for CaF2CaF_2 is 3.9×10−113.9 \times 10^{-11}. What is the molar solubility of CaF2CaF_2?

A

3.9×10−113.9 \times 10^{-11}

B

4.0×10−44.0 \times 10^{-4}

C

1.3×10−41.3 \times 10^{-4}

D

2.0×10−42.0 \times 10^{-4}

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