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AP Chemistry/Unit 7: Equilibrium
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Calculating Molar Solubility from Ksp
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The solubility product constant, $$K_{sp}$$, for $$CaF_2$$ is $$3.9 \times 10^{-11}$$. What is the molar solubility of $$CaF_2$$?

A

$$4.0 \times 10^{-4}$$

B

$$2.0 \times 10^{-4}$$

C

$$1.3 \times 10^{-4}$$

D

$$3.9 \times 10^{-11}$$

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