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AP Chemistry/Unit 7: Equilibrium
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Manipulating The Equilibrium Constant

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Consider an equilibrium reaction with an original Keq=10K_{eq} = 10. Four manipulations are performed:
(i) The reaction is reversed (resulting in K=1/10=0.1K' = 1/10 = 0.1).
(ii) The reaction is left unchanged (K=10K' = 10).
(iii) The coefficients are multiplied by 2 (yielding K=102=100K' = 10^2 = 100).
(iv) The coefficients are multiplied by 3 (yielding K=103=1000K' = 10^3 = 1000).
Rank these manipulations in order of increasing KeqK_{eq} (from lowest to highest). Provide your answer as an ordered list (e.g., “Reversed, Unchanged, Doubled, Tripled”).

A

Reversed, Doubled, Unchanged, Tripled

B

Unchanged, Reversed, Doubled, Tripled

C

Reversed, Unchanged, Doubled, Tripled

D

Tripled, Doubled, Unchanged, Reversed

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