Reaction Quotient and Equilibrium Shift
For the reaction , the equilibrium constant is $K = 0.5$. If a mixture is prepared with initial concentrations of $[\text{NO}_2] = 0.8 \, \text{M}$ and $[\text{N}_2\text{O}_4] = 0.2 \, \text{M}$, how will the reaction proceed to reach equilibrium?
A
The reaction shifts to the right because Q (≈ 0.3125) is less than K.
B
The reaction first shifts left then right due to kinetic factors.
C
No net shift occurs because Q equals K.
D
The reaction shifts to the left because Q is greater than K.
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