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AP Chemistry/Unit 7: Equilibrium
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Solubility Product Constant Calculation
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For the dissolution of calcium fluoride
$$\text{CaF}_2 (s) \rightleftharpoons \text{Ca}^{2+}(aq) + 2\text{F}^{-}(aq),$$
calculate the solubility product $$K_{sp}$$ using the values given in the table.

Ion Equilibrium Concentration (M)
$$\text{Ca}^{2+}$$ 1.0e-4
$$\text{F}^{-}$$ 2.0e-4
A

$$1.0 \times 10^{-4}$$

B

$$8.0 \times 10^{-12}$$

C

$$4.0 \times 10^{-12}$$

D

$$2.0 \times 10^{-8}$$

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