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AP Chemistry/Unit 7: Equilibrium
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Solubility Product Constant Calculation

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For the dissolution of calcium fluoride
CaF2(s)⇌Ca2+(aq)+2F−(aq),\text{CaF}_2 (s) \rightleftharpoons \text{Ca}^{2+}(aq) + 2\text{F}^{-}(aq),
calculate the solubility product KspK_{sp} using the values given in the table.

Ion Equilibrium Concentration (M)
Ca2+\text{Ca}^{2+} 1.0e-4
F−\text{F}^{-} 2.0e-4
A

8.0×10−128.0 \times 10^{-12}

B

2.0×10−82.0 \times 10^{-8}

C

4.0×10−124.0 \times 10^{-12}

D

1.0×10−41.0 \times 10^{-4}

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