Activation Energy and Spontaneity
Which property would BEST explain why the combustion of glucose (C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O, ΔG° = -2880 kJ/mol) doesn’t occur spontaneously at room temperature despite being highly exergonic?
A
Endothermic nature of the overall reaction
B
High activation energy requiring an initial input of energy
C
Positive entropy change opposing the reaction
D
Equilibrium constant less than 1
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