Gibbs Free Energy And Equilibrium Constant

Question

Using the data in the table for Reaction B, compute the equilibrium constant $$K$$ at $$T = 298\,K$$ using the relationship $$\Delta G^\circ = -RT\ln(K)$$. (Use $$R = 8.314\,	ext{J/(mol*K)}$$ and convert $$\Delta G^\circ$$ to Joules.)
 
| Reaction | $$\Delta G^\circ$$ (kJ/mol) |
|----------|-------------------------|
| A        | 20                      |
| B        | -10                     |
| C        | 0                       |

Accepted Answer

$$56.9$$

Answer

$$10.0$$

Answer

$$0.37$$

Answer

$$-56.9$$

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