Gibbs Free Energy And Equilibrium Constant

Question

Using the data provided for Reaction B, calculate the equilibrium constant, $$K$$, at $$T = 298\,	ext{K}$$. Use the equation $$\Delta G^\circ = -RT\ln(K)$$ with $$R = 8.314\,	ext{J/(mol}\cdot	ext{K)}$$.

| Reaction | $$\Delta G^\circ$$ (kJ/mol) |
|----------|-------------------------|
| A        | 20                      |
| B        | -10                     |
| C        | 0                       |

Accepted Answer

$$56.9$$

Answer

$$-56.9$$

Answer

$$10.0$$

Answer

$$0.37$$

Gibbs Free Energy And Equilibrium Constant

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