Analyzing a QuickSort Method Call

Question

Consider the `SortDriver` class below. What is the result of executing the `main` method?

```java
public class SortDriver {
    public static void main(String[] args) {
        int[] data = {5, 2, 8, 3};
        QuickSorter qs = new QuickSorter();
        qs.quickSort(data, 0, data.length - 1);
        System.out.println(java.util.Arrays.toString(data));
    }
}
```

Accepted Answer

quickSort is executed recursively, sorting the array in ascending order, and the sorted array is printed.

Answer

The output will be the original unsorted array because quickSort is not properly invoked.

Answer

Because QuickSort is inherently unstable, the final order of elements may be unpredictable.

Answer

Due to the static variable, quickSort is executed only once and the array remains unsorted.

Analyzing a QuickSort Method Call

Question Leaderboard