Java ThreadLocal Variable Behavior

Question

What is the consequence of using ThreadLocal for counter management in this multithreaded example?
 
```java
public class ThreadLocalExample {
    private static ThreadLocal<Integer> threadLocalCounter = ThreadLocal.withInitial(() -> 0);
    
    public static void increment() {
        threadLocalCounter.set(threadLocalCounter.get() + 1);
    }
    
    public static int get() {
        return threadLocalCounter.get();
    }
}
```

Accepted Answer

Each thread maintains its own counter, so there is no shared aggregation across threads.

Answer

An exception is thrown because ThreadLocal cannot be used with numeric values.

Answer

A race condition occurs because each thread updates the same global counter simultaneously.

Answer

Deadlock happens when threads wait for access to the ThreadLocal variable.

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