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Rate of Change of NO Concentration

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Using the graph of NO concentration given by N(t)=0.2∗t2−2∗t+40N(t)= 0.2*t^2 - 2*t + 40, determine the instantaneous rate of change at t = 5 hours.

A

-1 ppm per hour, which results from miscalculating the derivative.

B

0.5 ppm per hour, due to an error in differentiating the quadratic term.

C

0 ppm per hour.

D

2 ppm per hour, obtained by mistakenly substituting into the original function.

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