Acceleration from Position Function

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The position of a particle moving along the x-axis is given by $x(t) = 4\sin(\pi t)$ , where $x$ is in meters and $t$ is in seconds. What is the instantaneous acceleration of the particle at $t = 0.25$ s?

$-4 m/s^{2}$

$-2\pi^2\sqrt{2}\ \text{m/s}^2$

$4\pi\ \text{m/s}^2$

0 m/s²

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Question Leaderboard

Rank	User	Correct Count	Attempt Count	Total Time	Score
#1	dinhhoa	1	3	0m 00s	80
#2	muffinlim11	1	1	0m 48s	52
#3	khanakthukral	1	1	1m 16s	24
#4	sakurachu037	1	1	1m 27s	13
#5	mamix1038	0	2	0m 12s	-32
#6	rosalie.adair	0	2	0m 46s	-66
#7	ethan.yh.cui	1	1	3m 21s	-101
#8	aibekn386	1	3	3m 56s	-156
#9	ethann.homeacc	0	1	3m 07s	-197
#10	nicowrk	1	2	26m 38s	-1,508

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