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AP Physics 1/Unit 1 – Kinematics
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Average Acceleration from Velocity Vector

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The velocity of a particle moving in the xy-plane is given by the function v⃗(t)=(3t2i^+4t3j^)\vec{v}(t) = (3t^2 \hat{i} + 4t^3 \hat{j}) m/s, where tt is time in seconds. What is the magnitude of the particle’s average acceleration over the time interval from t=1t = 1 s to t=2t = 2 s?

A

513\sqrt{13} m/s²

B

913\sqrt{13} m/s²

C

865\sqrt{865} m/s²

D

13 m/s²

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