APFIVE Work Done by a Variable Force
A force F(x) = (6 - x²) N acts on a 1.0 kg object moving along the x-axis. If the object moves from x = -2 m to x = 2 m, which statement about the work done is correct?
A
The work cannot be determined without knowing the velocity
B
The work is zero because the force is symmetric about x = 0
C
The work is positive because the area above the x-axis exceeds the area below
D
The work is negative because the force opposes motion for x > 0
Question Leaderboard
| Rank | |||||
|---|---|---|---|---|---|
| #1 | lovesanrak25 | 1 | 1 | 0m 00s | 100 |
| #2 | onlyforstudy0427 | 1 | 1 | 0m 00s | 100 |
| #3 | daniel.kim | 0 | 1 | 0m 00s | -10 |
| #4 | jyhenry0828 | 1 | 2 | 3m 50s | -140 |
Items per page:
10
1 – 4 of 4