Rotational Dynamics of a Pulley System

Question

Two masses, $$m_1$$ and $$m_2$$ ($$m_1 > m_2$$), are connected by a light string that passes over a pulley with radius $$R$$ and moment of inertia $$I$$. Assuming the string does not slip, which of the following statements correctly describes the pulley's angular acceleration?

Accepted Answer

Angular acceleration is proportional to $$\frac{(m_1-m_2)gR}{I + (m_1 + m_2)R^2}$$

Answer

Angular velocity remains constant

Answer

Angular acceleration is proportional to $$\frac{(m_1+m_2)gR}{I}$$

Answer

Angular acceleration is zero regardless of mass values

Rotational Dynamics of a Pulley System

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