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AP Physics 2/Unit 11 – Electric Circuits
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Voltmeter Loading Effect

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The voltage across a resistor $R$ in a DC circuit is $V_0$. When a voltmeter with internal resistance $R_v$ is connected across the resistor, the measured voltage is $V_m$. Which of the following gives the ratio of the actual voltage to the measured voltage, $V_0/V_m$?

A

V0/Vm=1+R/RvV_0/V_m = 1 + R/R_v

B

V0/Vm=(R+Rv)/RvV_0/V_m = (R + R_v)/R_v

C

V0/Vm=Rv/(R+Rv)V_0/V_m = R_v/(R + R_v)

D

V0/Vm=1−R/RvV_0/V_m = 1 - R/R_v

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