Motional EMF and Terminal Velocity

Question

A conducting rod of mass `m` slides without friction down two parallel conducting rails inclined at an angle of 30° with the horizontal. The rails are a distance `L` apart and are connected at the bottom by a resistor of resistance `R`. A uniform magnetic field `B` is directed perpendicular to the plane of the rails. Which of the following expressions represents the terminal velocity of the rod?

Accepted Answer

$$\frac{mgR\sin(30^\circ)}{B^2L^2}$$

Answer

$$\frac{mgR}{BL\sin(30^\circ)}$$

Answer

$$\frac{mg\sin(30^\circ)}{BL}$$

Answer

$$\frac{mgR}{B^2L^2 \sin(30^\circ)}$$

Motional EMF and Terminal Velocity

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