Atomic Energy Level Transition
A mercury atom in an excited state emits a photon with wavelength 436 nm. If the atom is initially in a state with energy -3.2 eV, what is the energy of the final state? (h = 6.63×10⁻³⁴ J·s, c = 3×10⁸ m/s, 1 eV = 1.6×10⁻¹⁹ J)
A
-6.0 eV
B
0 eV
C
-0.4 eV
D
-2.8 eV
Question Leaderboard
Not enough data yet to show leaderboard.
APFIVE