Capacitor With Dielectric And Constant Voltage

Question

A parallel-plate capacitor connected to a battery has an initial electric field $$E_0$$ between its plates. A dielectric with constant $$\kappa$$ is then inserted between the plates while the battery remains connected. What are the resulting changes to the charge on the plates, the electric field, and the capacitance?

Accepted Answer

Charge increases, field remains constant, capacitance increases

Answer

Charge decreases, field decreases, capacitance increases

Answer

Charge remains constant, field decreases, capacitance increases

Answer

Charge increases, field decreases, capacitance increases

Capacitor With Dielectric And Constant Voltage

Question Leaderboard