Coaxial Cable Magnetic Field With Displacement Current

Question

A coaxial cable is composed of an inner conductor of radius $$a$$ and a concentric outer conductor with an inner radius of $$b$$. The current in the inner conductor varies with time as $$I(t) = I_0 \cos(\omega t)$$. Accounting for the displacement current, what is the expression for the magnetic field in the region $$a < r < b$$?

Accepted Answer

B = (μ₀I₀/2πr)cos(ωt)

Answer

B = (μ₀I₀/2πr)[cos(ωt) - (r²-a²)/(b²-a²)ω²ε₀μ₀sin(ωt)]

Answer

B = (μ₀I₀/2πr)[cos(ωt) - ω²ε₀μ₀sin(ωt)]

Answer

B = (μ₀I₀/2πr)[cos(ωt) + (r²-a²)/(b²-a²)ω²ε₀μ₀sin(ωt)]

Coaxial Cable Magnetic Field With Displacement Current

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