Magnetic Field Inside a Hollow Conductor

Question

A hollow cylindrical conductor with inner radius $$a$$ and outer radius $$b$$ carries a current $$I$$ that is uniformly distributed over its cross-section. What is the magnitude of the magnetic field at a distance $$r$$ from the central axis, where $$a < r < b$$?

Accepted Answer

$$B = \frac{\mu_0 I (r^2 - a^2)}{2\pi r (b^2 - a^2)}$$

Answer

$$B = \frac{\mu_0 I}{2\pi r}$$

Answer

$$B = \frac{\mu_0 Ir^2}{2\pi (b^2 - a^2)}$$

Answer

$$B = \frac{\mu_0 Ir}{2\pi (b^2 - a^2)}$$

Magnetic Field Inside a Hollow Conductor

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