Motional EMF and Applied Force

Mark

A square conducting loop of side length $L$ and resistance $R$ is pulled at a constant velocity $v$ from a region with a uniform magnetic field $B$ that is perpendicular to the loop’s plane. At the instant when half the loop’s area is within the field, what is the magnitude of the applied force required to maintain this constant velocity?

$F = \frac{B^2 L^2 v}{R}$

$F = \frac{B^2 L^2 v}{2R}$

$F = \frac{B^2 L v}{R}$

$F = BLv$

Hint

Did You Know?

Explain Why

Explain All Answers

Check Answer

Show Correct Answer

Report Question

Question Leaderboard

Not enough data yet to show leaderboard.

AI Tutor 1:23 AM

How can I help?

Email: apfive@apfive.orgPrivacy Policy