Electric Field of a Non-Uniformly Charged Rod

Question

A thin rod of length L has a linear charge density that varies according to the function $$\lambda(x) = \lambda_0 \left( \frac{x}{L} \right)$$, where x is the distance from one end. What is the magnitude of the electric field at a point P, located a distance d directly above the center of the rod?

Accepted Answer

E = (λ₀ L)/(8πε₀ d √((L/2)² + d²))

Answer

E = (λ₀/4πε₀)(1/d)(ln(4))

Answer

E = (λ₀/8πε₀)(1/d)(ln(4))

Answer

E = (λ₀/4πε₀)(L/d²)

Electric Field of a Non-Uniformly Charged Rod

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