APFIVE Acceleration Vector from Position Functions
A particle moves in the xy-plane such that its position as a function of time is given by $$x(t) = 3t^2$$ and $$y(t) = 4t - 5t^2$$. At $$t = 2$$ seconds, what is the direction of the particle’s acceleration vector, measured counterclockwise from the positive $$x$$-axis?
A
At an angle of 301° measured counterclockwise from +x
B
Directly toward the origin
C
Directly opposite to the velocity vector
D
Perpendicular to the velocity vector
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