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Centripetal Acceleration from Position Vector

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The position of a particle is given by the vector r⃗(t)=(3cos⁡(2t))i^+(3sin⁡(2t))j^ \vec{r}(t) = (3\cos(2t))\hat{i} + (3\sin(2t))\hat{j} , where position is measured in meters and time tt is in seconds. What is the magnitude of the centripetal acceleration at t=π/4 t = \pi/4 s?

A

24 m/s²

B

6 m/s²

C

12 m/s²

D

4 m/s²

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