Work Done by a Variable Force
A 1.0 kg object is displaced along the x-axis from x = -2 m to x = 2 m. During this displacement, a variable force F(x) = (6 - x²) N acts on the object. Which statement correctly describes the work done by this force?
A
The work is zero because the force is symmetric about x = 0
B
The work is negative because the force opposes motion for x > 0
C
The work is positive because the area above the x-axis exceeds the area below
D
The work cannot be determined without knowing the velocity
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