Total Momentum of a Particle System
A system consists of three particles with the following momenta: p⃗₁ = (2.0î - 3.0ĵ) kg·m/s, p⃗₂ = (-4.0î + 1.0ĵ) kg·m/s, and p⃗₃ = (6.0î + 5.0ĵ) kg·m/s. As a result of an internal explosion, the momentum of the first particle doubles in magnitude while maintaining its direction. What is the new direction of the system’s total momentum?
A
56.3° above the positive x-axis
B
18.4° above the positive x-axis
C
0° above the positive x-axis
D
33.7° above the positive x-axis
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