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Moment of Inertia of a Drilled Sphere
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A solid sphere of radius $$R$$ and mass $$M$$ has a cylindrical hole of radius $$R/2$$ drilled symmetrically through its center, with the axis of the hole coinciding with a diameter of the sphere. What is the moment of inertia of the resulting object about the axis of the hole?

A

$$\frac{31}{80}MR^2$$

B

$$\frac{2MR^2}{5}$$

C

$$\frac{MR^2}{2}$$

D

$$\frac{2MR^2}{5} - \frac{MR^2}{4}$$

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