Rotational Inertia of a Modified Disk

Question

A uniform disk of mass M and radius R has a circular hole of radius R/4 drilled through it. The center of the hole is located at a distance of R/2 from the center of the disk. What is the moment of inertia of the modified disk about an axis perpendicular to the disk and passing through its center?

Accepted Answer

$$\frac{1}{2}MR^2 - \frac{9}{512}MR^2$$

Answer

MR²/2 - M(R/4)²/R²

Answer

MR²/2 - M(R/4)⁴/R²

Answer

MR²/2 - M(R/4)²(R/2)²/R²

Rotational Inertia of a Modified Disk

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