| preferred AP College board partner for AP classes
hard
Work-Energy For Rotation And Rolling
< Prev
Next >

A wheel of mass $$M$$, radius $$R$$, and moment of inertia $$I$$ rotates with initial angular velocity $$\omega_0$$ about a fixed axle and is brought to rest by a constant frictional torque $$\tau$$. The stopping arc length covered before stopping is $$d_{\text{rotation}} = R\theta_{\text{rotation}}$$. If the same wheel rolls without slipping on a horizontal surface with initial linear speed $$v_0 = \omega_0 R$$ (and therefore initial angular speed $$\omega_0$$), and is slowed to rest by the same constant frictional torque $$\tau$$ (applied at the axle), what is the ratio $$\dfrac{d_{\text{rolling}}}{d_{\text{rotation}}}$$, where $$d_{\text{rolling}}$$ is the stopping distance for rolling and $$d_{\text{rotation}}$$ is for pure rotation?

A

$$d_{\text{rolling}} = d_{\text{rotation}}$$

B

$$d_{\text{rolling}} = d_{\text{rotation}} \cdot \left(1 + \frac{I}{MR^2}\right)$$

C

$$d_{\text{rolling}} = d_{\text{rotation}} \cdot \left(1 + \frac{MR^2}{I}\right)$$

D

$$d_{\text{rolling}} = d_{\text{rotation}} \cdot \frac{I}{MR^2}$$

Hint
Did You Know?
Explain Why
Explain All Answers
Check Answer
Show Correct Answer
Report Question

Question Leaderboard

Not enough data yet to show leaderboard.

No comments yet. Be the first to comment!

AI Tutor

How can I help?

APFIVE © 2020.
Email: [email protected]|Privacy Policy