Power Dissipated by Friction on a Slipping Rod

Question

A uniform rod of length L and mass M is initially at rest in a vertical position on a rough horizontal surface. The rod is released and begins to fall, slipping on the surface. Which of the following expressions represents the instantaneous power dissipated by friction when the rod makes an angle θ with the vertical?

Accepted Answer

$$μₖMg\left|\dot{x}_{	ext{cm}} + \frac{L}{2}\cos(	heta)\dot{	heta}ight|$$

Answer

$$μₖMg(Lθ̇/2)cos(θ)$$

Answer

$$μₖMgLθ̇sin(θ)$$

Answer

$$μₖMg(Lθ̇/2)sin(θ)(1-cos(θ))$$

Power Dissipated by Friction on a Slipping Rod

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