Period of an Oscillating Hoop

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A physical pendulum consists of a thin hoop of radius $R$ pivoted at its rim. If the pivot is moved to a point at a distance $R/2$ from the center, what is the ratio of the new period to the original period?

$2/3$

$\sqrt{2}$

$\frac{\sqrt{5}}{2}$

$\sqrt{3/2}$

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