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Pythagorean Identity Transformation

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Which expression results from dividing both sides of the Pythagorean identity sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1 by cos2θ\cos^2\theta?

A

sec2θtan2θ=0\sec^2\theta - \tan^2\theta = 0

B

1+tan2θ=sec2θ1 + \tan^2\theta = \sec^2\theta

C

1tan2θ=sec2θ1 - \tan^2\theta = \sec^2\theta

D

tan2θ+1=csc2θ\tan^2\theta + 1 = \csc^2\theta

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