Trigonometric Identity Simplification
Where both expressions are defined, which of the following is equivalent to $$\frac{\sec^2 x - 1}{\sec^2 x}$$?
A
$$\sin^2 x$$
B
$$\frac{\cos^2 x}{\tan^2 x}$$
C
$$\cos^2 x$$
D
$$\frac{\tan^2 x}{\sin^2 x}$$
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