Trigonometric Identity Simplification

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Which of the following is equivalent to the expression $\frac{\sec^2 x - 1}{\sec^2 x}$ ?

$\frac{\tan^2 x}{\sin^2 x}$

$\frac{\cos^2 x}{\tan^2 x}$

$\cos^2 x$

$\sin^2 x$

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