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Trigonometric Identity Simplification
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Where both expressions are defined, which of the following is equivalent to $$\frac{\sec^2 x - 1}{\sec^2 x}$$?

A

$$\sin^2 x$$

B

$$\frac{\cos^2 x}{\tan^2 x}$$

C

$$\cos^2 x$$

D

$$\frac{\tan^2 x}{\sin^2 x}$$

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