Consider the curve defined by the equation xy+2x−3y=6xy + 2x - 3y = 6xy+2x−3y=6. What is dydx\frac{dy}{dx}dxdy?
dydx=−(x−3)y+2\frac{dy}{dx} = \frac{-(x-3)}{y+2}dxdy=y+2−(x−3)
dydx=x−3y+2\frac{dy}{dx} = \frac{x-3}{y+2}dxdy=y+2x−3
dydx=−(y+2)x−3\frac{dy}{dx} = \frac{-(y+2)}{x-3}dxdy=x−3−(y+2)
dydx=y+2x−3\frac{dy}{dx} = \frac{y+2}{x-3}dxdy=x−3y+2
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AI Tutor 11:50 PM
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