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Parametric Curve Secant Line Slope

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The path of a particle is described by the parametric equations x(t)=t3−3tx(t) = t^3 - 3t and y(t)=t2y(t) = t^2 for t∈[0,2]t \in [0, 2]. What is the slope of the line connecting the particle’s position at t=0t = 0 and its position at t=2t = 2?

A

22

B

42\frac{4}{2}

C

12\frac{1}{2}

D

−12-\frac{1}{2}

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