Speed From a Position Vector

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A particle’s motion in a plane is described by the position vector $\mathbf{p}(t) = (3t^2 - 2t, 4t + 1)$ . What is the particle’s speed at time $t = 2$ ?

$\sqrt{26}$

$2\sqrt{26}$

$26$

$4\sqrt{26}$

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