Velocity Vector and Magnitude from Position

Question

The position of a particle in the plane at time $$t$$ is given by the vector function $$\vec{p}(t)=(2*t+1)\,\mathbf{i}+(3*t-2)\,\mathbf{j}$$. Which of the following gives the velocity vector and its magnitude at time $$t=2$$?

Accepted Answer

$$\vec{v}(2)=\langle 2,3angle\quad 	ext{with magnitude } \sqrt{13}$$

Answer

$$\vec{v}(2)=\langle 4,5angle\quad 	ext{with magnitude } \sqrt{41}$$

Answer

$$\vec{v}(2)=\langle 2,3angle\quad 	ext{with magnitude } 5$$

Answer

$$\vec{v}(2)=\langle 2*t,3*tangle\quad 	ext{with magnitude } \sqrt{(2*t)^2+(3*t)^2}$$

Velocity Vector and Magnitude from Position

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