I. To evaluate $$\lim_{x\to0} \frac{\sqrt{x+4}-2}{x}$$, one can rationalize the numerator, leading to the simplification: $$\frac{\sqrt{x+4}-2}{x} \times \frac{\sqrt{x+4}+2}{\sqrt{x+4}+2} = \frac{x}{x(\sqrt{x+4}+2)} = \frac{1}{\sqrt{x+4}+2}$$.

II. Taking the limit as $$x\to0$$ in the simplified expression yields $$\frac{1}{\sqrt{4}+2} = \frac{1}{4}$$.

III. The limit does not exist because the original function is undefined at $$x = 0$$.

Which of the above statements about evaluating the limit is true?